theorem srecpauxeq2 (A: set) (_n1 _n2: nat): $ _n1 = _n2 -> srecpaux A _n1 = srecpaux A _n2 $;
_n1 = _n2 -> _n1 = _n2
_n1 = _n2 -> srecpaux A _n1 = srecpaux A _n2