theorem rlreceq3 (z: nat) (S: set) (_n1 _n2: nat): $ _n1 = _n2 -> rlrec z S _n1 = rlrec z S _n2 $;
_n1 = _n2 -> _n1 = _n2
_n1 = _n2 -> rlrec z S _n1 = rlrec z S _n2