theorem Sndss (A B: set): $ A C_ B -> Snd A C_ Snd B $;
A C_ B -> b1 a1 e. A -> b1 a1 e. B
A C_ B -> {a1 | b1 a1 e. A} C_ {a1 | b1 a1 e. B}
A C_ B -> Snd A C_ Snd B